n! = n · (n – 1)!
5! = 5 · 4 · 3 · 2 · 1
5! = 5 · (4 · 3 · 2 · 1)
5! = 5 · (4!)
factorial
first determines whether the terminating condition number <= 1 is Truefactorial
returns 1 return
statement expresses the problem as the product of number
and a recursive call to factorial
that evaluates factorial(number - 1)
factorial(number)
factorial
must receive a nonnegative argumentdef factorial(number):
"""Return factorial of number."""
if number <= 1:
return 1
return number * factorial(number - 1) # recursive call
factorial
for the values 0-10for i in range(11):
print(f'{i}! = {factorial(i)}')
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